Increasing bearing area to decrease friction: Difference between revisions

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Created page with " Unlike friction in macroscale bearings, <br> friction in atomically precise diamondoid slide bearings ... * is dominated by dynamic friction <br>(which scales quadratica..."
 
 
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Friction in [[atomically precise diamondoid slide bearing]]s ...
* is dominated by dynamic friction <br>which scales quadratically with speed: <br>1/2x speed => 1/4x friction | 1/10x speed => 1/100x friction
* is proportional to the bearing area (2x area => 2x friction)
For details see: [[Friction]]


Unlike friction in macroscale bearings, <br>
Side-note: <br>
friction in [[atomically precise diamondoid slide bearing]]s ...
Low speed friction in macroscale bearings is quite different as it is <br>
* is dominated by dynamic friction <br>(which scales quadratically with speed: 1/2x speed => 1/4x friction | 1/10x speed => 1/100x friction)
speed independent, area independent, load dependent.
* is proportional to the bearing area (2x area => 2x friction)


== The trick ==
== The trick ==
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* Halving speed and  
* Halving speed and  
* doubling machinery
* doubling machinery
Keeping total throughput constant leads to
(this keeps the total throughput constant) leads to
* quartering friction losses due to reduced bearing speed
* quartering friction losses due to reduced bearing speed
* doubling friction losses due to increased bearing area
* doubling friction losses due to increased bearing area
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'''Q:''' But isn't doubling the amount of machinery a problem? <br>
'''Q:''' But isn't doubling the amount of machinery a problem? <br>
'''A:''' No! <br>
'''A:''' No! There is exceptionally little machinery needed to  <br>
There is exceptianally little machinery needed to  <br>
get practical levels of throughput (aka product production rate). <br>
get practical levels of throughput (aka product production rate). <br>
This is to the [[scaling law]] of [[higher throughput of smaller machinery]].
This is due to the [[scaling law]] of [[higher throughput of smaller machinery]].
 
=== Math ===
 
* P … (wearless) frictive losses – in W
* A … bearing area – in m²
* n … number of [[sub layers]] – an integer
* v … speed of assembly … in m/s
* gamma … dynamic friction coefficient – W/(m²*(m/s)²)
 
<math> P = \gamma A n v^2 </math> <br>
Applying the trick: <br>
<math> P' = \gamma A (x n) (v/x)^2 </math> <br>
<math> P' = \gamma A n v^2 /x </math>
 
Related: [[Compenslow]]
 
This has limits though!


== Limits to the trick ==
== Limits to the trick ==
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At some point assembly motions reach become similarly slow as the assembly motions. <br>
At some point assembly motions reach become similarly slow as the assembly motions. <br>
At this point adding further [[sub-layers]] there is no further reduction of frictive losses but rather frictive losses ride again. (eventually linearly).
At this point adding further [[sub-layer]]s there is no further reduction of frictive losses but rather frictive losses ride again. (eventually linearly).


== Applications cases ==
== Applications cases ==
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== Related ==
== Related ==


* '''[[Optimal sublayernumber for minimal friction]]'''
* '''[[Deliberate slowdown at the lowest assembly level‎]]'''
* [[Friction]], [[Superlubricity]]
* [[Friction]], [[Superlubricity]]
* [[Infinitesimal bearings]]
* '''[[Infinitesimal bearings]]'''
* [[Higher throughput of smaller machinery]]
* [[Higher throughput of smaller machinery]]
* [[Mesoscale friction]]
* [[Higher bearing surface area of smaller machinery]]
[[Category:Surprising facts]]

Latest revision as of 22:36, 29 March 2026

Friction in atomically precise diamondoid slide bearings ...

  • is dominated by dynamic friction
    which scales quadratically with speed:
    1/2x speed => 1/4x friction | 1/10x speed => 1/100x friction
  • is proportional to the bearing area (2x area => 2x friction)

For details see: Friction

Side-note:
Low speed friction in macroscale bearings is quite different as it is
speed independent, area independent, load dependent.

The trick

This allows for a neat trick:

  • Halving speed and
  • doubling machinery

(this keeps the total throughput constant) leads to

  • quartering friction losses due to reduced bearing speed
  • doubling friction losses due to increased bearing area

Overall a halving of friction.

Q: But isn't doubling the amount of machinery a problem?
A: No! There is exceptionally little machinery needed to
get practical levels of throughput (aka product production rate).
This is due to the scaling law of higher throughput of smaller machinery.

Math

  • P … (wearless) frictive losses – in W
  • A … bearing area – in m²
  • n … number of sub layers – an integer
  • v … speed of assembly … in m/s
  • gamma … dynamic friction coefficient – W/(m²*(m/s)²)

<math> P = \gamma A n v^2 </math>
Applying the trick:
<math> P' = \gamma A (x n) (v/x)^2 </math>
<math> P' = \gamma A n v^2 /x </math>

Related: Compenslow

This has limits though!

Limits to the trick

See math on main page: Limits to lower friction despite higher bearing area

  • assembly motions can be slowed down by adding more sub layers.
  • transport motions can not be slowed by adding more sub layers.

At some point assembly motions reach become similarly slow as the assembly motions.
At this point adding further sub-layers there is no further reduction of frictive losses but rather frictive losses ride again. (eventually linearly).

Applications cases

Related